next up previous
Next: Initial condition Up: Heat equation. Fourier method Previous: III.

The general solution

For each

\begin{displaymath}
G_n (x) = \sin(\frac{ \pi n x }{ L } ),\;\;n=1,\;2,\;\dots
\end{displaymath}

we can find $F_n(t)$ by solving the differential equation

\begin{displaymath}
\frac{d} {dt } F(t) = -(\frac{ \pi n }{ L })^2 F(t)
\end{displaymath}

which follows from (1.1) with $ \lambda = -(\frac{ \pi n }{ L })^2.$ The general solution for this equation is

\begin{displaymath}
F_n(t) = C_n e^{-(\frac{ \pi n }{ L })^2 t },
\end{displaymath}

where the constant $C_n$ is arbitrary. Hence, we have infinitely many special solutions

\begin{displaymath}
C_n e^{-(\frac{ \pi n }{ L })^2 t } \cdot \sin(\frac{ \pi n x }{ L } ) ,\;\;n=1,\;2,\;\dots
\end{displaymath}

for the heat equation with the boundary conditions

\begin{displaymath}
u(t,0)=0,\;\; u(t,L) = 0
\end{displaymath}

The general solution corresponding to these boundary conditions is given by
\begin{displaymath}
u(t,x) = \sum_{n=1}^\infty C_n e^{-(\frac{ \pi n }{ L })^2 t } \cdot \sin(\frac{ \pi n x }{ L } )
\end{displaymath} (1.3)



Sergey Nikitin 2004-10-25